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0=12q^2-16q+24
We move all terms to the left:
0-(12q^2-16q+24)=0
We add all the numbers together, and all the variables
-(12q^2-16q+24)=0
We get rid of parentheses
-12q^2+16q-24=0
a = -12; b = 16; c = -24;
Δ = b2-4ac
Δ = 162-4·(-12)·(-24)
Δ = -896
Delta is less than zero, so there is no solution for the equation
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